Question

Question 6 Which of the following bonds in the tertiary amine shown, CANNOT be formed via reductive amination? Select all that apply.

Question 7 The following reaction will not proceed as written. Clearly explain why this reaction will not occur.

Question 10  For each of the following pairs of molecules, indicate the compound containing the most acidic proton.

Answer 1

Question 6

In reductive amination, primary amine react with aldehyde or ketone we get secondary amine followed by another aldehyde or ketone we get tertiary amine as a product.

therefore two successive reductive amination produces tertiary amine hence trisubstitued carbonyl compound is not possible hence 2-methyl-2-propanamine taken as amine while others cyclohexanone and propanal taken to get the tertiary amine as given below

CO EAN e Ik Ans: А

When LDA react with alpha hydrogen containing carbonyl compound, LDA abstract alpha hydrogen to produce enolate. Now enolate act as nucleophile undergo SN2 alkylation hence alkyl halide should be primary if tertiary alkyl halide here not possible to backside attack hence no reaction occurs.

•Br 8 cion LDA HO → No reaction

Question 10

Based on Inductive effect, when greater -I effect group present in a molecule greater acid strength. hence compared to A and B, A has Cl and B has Br Chloro is greater -I effect (more electronegative) than bromo therefore A is more acid strength

Ans: A

Compared to aldehyde has alpha hydrogen is more acidic rather than that of  ester containing alpha hydrgogen aldehyde more polar rather than less polar ester

Ans: C