Question

Four copper wires of equal lengths are connected in series. Their cross sectional areas are 1.00cm², 2.00cm², 3.00cm² and 5.00cm². If the voltage of 120V is applied to the arrangement, what is the voltage across the 2.00cm² wire?

NB: length of wires could be anything but the length is the same

Answer 1

Solution:- We know that the formula for the Resistance of wire R= sl A et & Resisticity of coppes wire length of the wire At cross-sectional area of wise In given problem fous wires are connected in series. all wires are of same dength different epossectional ded, when the resistance are connected in series, dength and R = Rif Raf R₂ f R4 shef slo fler flz AL f AI Az AL (dada=dz=1 4 = 1) se + (YA,+ 1 - 2 f Yas IAL = se ( + + *$*$) 4 = se (2.033 (m²) R-se (2.093 7 10 4 m2) Voltage v= 1200 is applied to the arrangement To tell cursent in the cismit so, I=U/R Scanned by TapScanner

1200 e ( 2 -033 x 4 ) we then know that when the resistances are connected in series russent across each resistance is same I. the resistance has the cross-sectional So, the area curent across 2 cm² is also 1200 I = se (2-033 xble in 2) Now, the potential difference across the 2.00cm² colse is, V-IR 1200 & I 2.00 x 104 cm2 se (2-033 y 184 m2) V= 120v +4 2-033 x 10 m2 x 2-00 X10 2 m V- 29.51 v so, voltage a cress the 2.00 cm² wire is 29.5iv. Scanned by TapScanner