Question

hi i know the answer i just need an in depth explanation on how to do this question including the formula, how to change the formula, proper vocabulary that is relevant to this question etc, here is the question pls reply in 20m

The molar heat of vapourization of acetone, C3H6O, is 30.3 kJ/mol at its boiling point. Describe the the energy changes resulting from physical change (vapourization/condensation of acetone) in terms of whether energy is released or absorbed. How much heat would be liberated by the condensation of 28.00 g of acetone?

also make sure it is simple and easy to understand not too complex pls

Answer 1

1 30.3 k . Given_molar heat of Vapowrisation of vacetone is KI/mde vondensation ģ_28.009 Then camount heat Converting grams in moles. of 28.00g of acetoner required ist moles grams x 1 mole grams acetone 28.0og ug moles 28 X 58.1 moles 0.481 9277

Heat Liberated noles & heat of Vapourisation 0:48192 X 30.3 KJ 14.60 KJ .: 14.60 KJ heal released ation: by condens-