Question

hi i know the answer i just need an in depth explanation on how to do this question including formulas, formula changes, proper vocabular etc, anyhing that is relevant to this question inncluding ice charts, etc please make sure this explanation is simple and not too complex to understand, thank you, the question is:

A solution was made by dissolving 0.837 g Ba(OH)2 in 100 mL final volume. If Ba(OH)2 is fully broken up into its ions, what is the pOH and the pH of the solution?

Answer 1

Molarity of BaßH Solution = Moles of Balohe Volume of solution 0-8379 / 17 171.3 glomal 100 x103 L 0.0489 molfh. 0.0489 M 2+ BACH Ba + 204 IM Balth dissociates into EM OUT 0.0489 M Baby > 2X0.0489 M oth 0.0978 M ,