Question

Test whether 14 <H2 at the c = 0.05 level of significance for the sample data shown in the accompanying table. Assume that the populations are normally distributed. B! Click the icon to view the data table, Determine the null and alternative hypothesis for this test. Sample Data O A. Ho:H1 = H2 H:H *H2 OB. Ho H1 H2 HEM1 =12 @ C. Hp-Hifl2 H:H1 H2 OD. Ho H1 = H2 H:H1 <H2 n Population 1 31 103.5 12.3 Population 2 25 114.5 13.2 S Detemine the P-value for this hypothesis test. Print Done P= 6 (Round to three decimal places as needed.) State the appropriate conclusion. Choose the correct answer below. O A. Reject Ho. There is sufficient evidence at the a= 0.05 level of significance to conclude that 14 <H2- OB. Reject Ho. There is not sufficient evidence at the a= 0.05 level of significance to conclude that un <H2. O C. Do not reject Ho. There is not sufficient evidence at the a = 0.05 level of significance to conclude that 17 <H2- OD. Do not reject Ho. There is sufficient evidence at the a=0.05 level of significance to conclude that Hy <H2.

Answer 1

Answer: bivere that L-0.05 population - 1 populations-a r2 = 25 Xa = 114.5 X = 103.5 si 12.3 9a. = 13.2 Test Hyrothesis: Ho: M, =la Ng Hi u, kur - Test statistic: T car xo - Xa 103.5 - 114.5 5,2 + 52? Па. (12-3)2 (13.2) 25 3.4423 P value - 3.195537 p[tetcai] p(x-3.195) 0.001 which less thari 2 = 0.05 0.0010.05 Ho there Reject is sufficieril evidence at the 2=0.05 level of significarece to corefiderece Hatimo Ma