Question

Water at 20° flows in pipeline system shown below (Fig.1) at rate of 32400 1hr. Pipe 1 is 15m long and 0.044 m outer diameter and pipe 2 is 100m long and 0.034m outer diameter. The thickness of both pipes is 2mm. Pipe 1 is a ductile iron uncoated pipe and pipe 2 is ductile iron coated pipe. There are totally 4 elbows in the system (two elbows in each pipe) and the elbows are 90° street elbows. All pipes are located on the same elevation. Consider major loss and minor loss for both pipes. 1. Calculate the flow rate and head loss in each pipe (10 marks) 2. Calculate the pressure drop between point A and point B located on either sides of the main pipeline (5 marks) Note: Attach your calculation on moody diagram to the solution. This forms part of total mark. Branch 1 Main Pipe B Main Pipe Branch 2 Fig. 1

Answer 1

Clode wise - +) 0.061 44-2 = 0.061 42 E, = 0.12 = 0.00375 Sofa Discharge, om System 32900 kr948 discharge pipe 1 & pipe 2 2. = 64s Py = -34% ech- Relative Roughness of pipes, (E= 0.061 mm ter ductile irone 20.00/45 uncoated) Relative Longinus of pipe 2, E2 - 0.12 (6 = 0.12 mm for duetile iron, coated pribe). kinematic Viscosity of water at 20°C, V = 1.00 4x10 m/s ED Pe=VD friction ho hay Q(es) (m 105 (x1050 factor of the agd Brancha 6 -7.46 375 2.38 -196.02 69264-94 Corrected diharge, AB =-(-196.02) 2E 2x69264.94 4QP = 0.0014151 Pipe discharge Pipe Assumed Velocity 4.33 145 1-811 0.023 7.8496 1308.267 0.028 -203.87 67956.67 Branch2 -3 m3 1.415 15 ls Corrected disch Q = G+AQ 6+1.915 =1 7.415 l/ - 3+1.415 = - 1.585 l/s. 1

Łhe flv 5-35 10.02 2 1602.02 lo 275 1612295 ک And ihration : - (kertonu = 05) +2key Pibe QUI) Yme) sem 7.415 145 2.24 11879 2 -1.585 -1.971 375 0.628 10.026 -16.2858 4.4068 corrected AQ-Ehr -(-4.40682 Discharge 24h/Q 2x 1612.295 AQ = 0.00/3676m316 = 7.3166 l/s Pipe Corected discharge, p2p+4Q 1. 7.415 + 1.3666 8.7876 Us 2. -1.585 + 1.3661 2 2184/9 1 ago *703 E 3xd iteration : + 2 ke 2/2 Libe. Ples) VRIEL LED in F Thatari 8.78/ 1634 145 2.65 10.022 18.146 2066.367 2 -0.284 0.271 375 0.086 0.032 -0.378 1730.77 17.768 3797.13 Coreeted elschorze 90 che 519407009 REhya 2x3797.13 AQ=-0.002339 fm?s =-2.339664/5 Pape Conected olischarge Q2Q+AG 8.78/-2.33966 = 6.49794 Ils -0.484 – 2-33966 2 2.5589/5. 2 Aus in Branch 1, CQ, Discharge 6.442 1/5 Discharge in Branch 2 (Q₂ = 2.5584. Any Head loss in fape 1, H₂, of Liv 2 2 Kebook? 299 19

02.02 0.275 212.295 Q = 6.4421/4 0.006442 m3 V = 60-806442)/(0.042) 4.6498 m/ he a vo 4.1998X 0.042 e 1.945x105 1.004610-6 E/= 145x105 Using Moody Diagrams: friction factor, f26.024. Head loss, H 2 0.024815x [4.6498)2+ 2x0.5%(406498)2 2x9.8180.042 249.81 [112,2 10.547 m! Ay 27 -367 77 7.13 ELO Q2 = 2.558 l/ z 0.002558 m3/s. V = 3.1806 m/s RecV 3.1806X0-032 = 1.013X105 1.004 x 106 2375x105 Using Moody diagram, Head loss in priße 2, 4, 20.03X100 x (318)?/ 240:5X (3•18)2 2x9.87X0.032 2109.81 TH= 48.88m. Ay $20.03. Bernoullis equation (2) Applying PA + V equation b/w point Ar +/+ H2 = Po Sw 74 + ig Tw my VAZ V² ZA ZB