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QUESTION 12 A sample of size 100 is chosen from a population. The sample mean is 100 and the standard deviation is 15. Find t
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Answer #1

a = 1-0.95 = 0.05

t_{\alpha/2}=t_{0.025}=1.984

\bar{x}=100

s = 15

Upper limit =\bar{x}+t_{0.025}*\frac{s}{\sqrt{n}}

                  =100+1.984*\frac{15}{\sqrt{100}}

                  = 102.976

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