Question

1\2 A B с D W X 5,6 4,20 2, 11 8,8 5,10 18,2 12,0 5,8 Y 7,3 10,2 4,6 3, 16 Z 7, 11 5, 10 6,1 10,6 QUESTION 2. (35 pts) Using
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Answer #1

Answer:

There is no pure strategy Nash equilibrium in this game:

The initial matrix of payoffs:

2
W X Y Z
1 A 5, 6 4, 20 7, 3 7, 11
B 2, 11 8, 8 10, 2 5, 6
C 5, 10 18, 2 4, 6 6, 1
D 12, 0 5, 8 3, 16 10, 6

We see that Player 1 will never play A. So we can eliminate the first row, A:

2
W X Y Z
1 A 5, 6 4, 20 7, 3 7, 11
B 2, 11 8, 8 10, 2 5, 6
C 5, 10 18, 2 4, 6 6, 1
D 12, 0 5, 8 3, 16 10, 6

Now, Player 2 will never play Z, it can be eliminated:

2
W X Y Z
1 A 5, 6 4, 20 7, 3 7, 11
B 2, 11 8, 8 10, 2 5, 6
C 5, 10 18, 2 4, 6 6, 1
D 12, 0 5, 8 3, 16 10, 6

Out of the remaining cells. Player 1 will never play C. Let us eliminate C:

2
W X Y Z
1 A 5, 6 4, 20 7, 3 7, 11
B 2, 11 8, 8 10, 2 5, 6
C 5, 10 18, 2 4, 6 6, 1
D 12, 0 5, 8 3, 16 10, 6

Next, Player 2 will not play X. It can be eliminated:

2
W X Y Z
1 A 5, 6 4, 20 7, 3 7, 11
B 2, 11 8, 8 10, 2 5, 6
C 5, 10 18, 2 4, 6 6, 1
D 12, 0 5, 8 3, 16 10, 6

Now, Player 1 will not play B for Player 2's W, and D for Player 2's Y. They can be eliminated:

2
W X Y Z
1 A 5, 6 4, 20 7, 3 7, 11
B 2, 11 8, 8 10, 2 5, 6
C 5, 10 18, 2 4, 6 6, 1
D 12, 0 5, 8 3, 16 10, 6

Player 2 will never play Y for Player 1's B and W for Player 1's D. These can also be eliminated:

2
W X Y Z
1 A 5, 6 4, 20 7, 3 7, 11
B 2, 11 8, 8 10, 2 5, 6
C 5, 10 18, 2 4, 6 6, 1
D 12, 0 5, 8 3, 16 10, 6

Now there is nothing left for the players to check for elimination.

There is no pure strategy Nash equilibrium to this game.

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