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A ball of mass 0.25 kg is suspended by two strings as shown in the diagram below. (a) Determine the weight of the ball, in N,
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V530 37° casing I sin37 To 53 Tacos 37 T, COS 530 mg mg Given mass of ball = 0.25kg mg weight of the ball wa - 0.25810 - 2.Ta [ 1.064 +0.6 6] - 2.5 22.5 Ta [10664 2.5 Ta ܕܓ 664 N = 1.5024 T, = 1.33 Ta (1-33) (5024) le 998 N W - 2.5 N weight Tension

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