Question

You are the designer for the proposed Serdang incinerator located in Kolej 10 in UPM. however, the only information available for the design of the incinerator are the waste composition at the waste collection centre at kolej 10. these wastes are the ones going to be fed into the proposed incinerator, the information of the waste composition a given as fellows. composition Moisture content, % Wet weight kg 30 70 25 Food waste Paper plastics Wood Metals 6.5 4 Calorific heat value, kJ/kg-dry weight 2000 7200 14000 8000 300 15 50 10 20 1 The incinerator which is of a rotary kiln type is going to have an average energy release rate of 28500 kJ/hr-m in the combustion chamber it is anticipated that the incinerator will be used to incinerate 4000 kg/hr of solid waste. the heating value (specific energy content) of the waste can be obtained from the waste composition information given above. assume that the length - to - diameter ratio of the incinerator is 3.5. assume the incinerator is of cylindrical shape. design the size of the incinerator in terms of volume, diameter and length

Answer 1

Sol. ne find cry not of each component net not Bo Bj not Tood neste Paper Plastics hood 25 15 lo lo M 30x0.3=9 0.185 JS XO-938=93.375 0.376 Isxo.al = 14.4 o-roll loxoos = 5 0.069. Joxo-99 = 1968. 0.976. Tota Metal = 1.575 lpmin= (6-195x2000)+(0.3% * 7200) +(0» 2011 X 14000) + Cooobex booo)-(300x8=976) Apmix = 604701 KI / ugogo Now, &- 20500 KJ/hm V- 2011 .. H = 3-5 423-5D. V=23-50² OV= 4000 Hmin ge500 40*3-6))= 4000x604701 D3=848-715 x4 308X3014 DE 306.4.1 ID=6.75m H = 23.685 m V= 3-14 (6:35) 223-695 1844.90 m

using given data and energy balance we can find the required design of kiln

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