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D Question 29 1 pts Balance the following redox reaction using the half-reaction method in acidic solution. MnOd() + Fe2(04)
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Answer #1

29)Answer-

Half-reaction-

Fe2+ ------>Fe3+

Mno4- ----->Mn2+

Balance in acidic solution

Ferrous ion is oxidized:

Fe2+ ------>Fe3+ + e-

And permanganate ion is reduced:

5e- + 8H+ + Mno4- ------> Mn2+ + 4H2O

Equalize electrons-

5Fe2+ ----> 5Fe3+ + 5e-

5e- + 8H+ + Mno4- ---->Mn2+ + 4H2O

Add-

8H+ + Mno4- + 5Fe2+ ------->5Fe3+ + Mn2+ + 4H2O

5th option is the correct answer.

Coefficient in front of Fe2+ is 5.

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