Question

(b) Calculate the maximum in-plane shear stress Imax on the outer surface of the pipe at point kif there is an internal pressure of 3600 kPa inside the pipe. (Note: Enter the absolute value here.) Tax for point- MPa For this analysis, use the following values: Distances, Loads, and Moments a - 250 mm P. - 19 KN P. - 29.5 kN T-10 kN m (a) Calculate the maximum in-plane shear stress Tmax at point Hon the outer surface of the pipe if there is no internal pressure (i.e.,p- OkPa). (Note: Enter the absolute value here.) Tmax for point H- MPa
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Answer 1

Given, a=400 mm, Pro 40.SIN Py = 69.5kn T= 35 kNm Do = 175 mm, t=6mm Ro = 07.5 mm Ri= B1: 5 mm 1 Pol.com Moment o inestia (ID)': Ipa * CRO"-Rih) a [ 87.54-8115] 2 Ip = 22774471.71 mm" 2 Moment of inertia (I): Iz = t[Rot-Ri"] IP Iz = 1138723 5.86 mm XED Due to TOY Sion Due to wad Py 1 Due to load Pn . Shecor stress at point H is due to Torsion & load Pa Dwow shear stress due to tosision Т. Tmax Тр Tmax

Zmax = 1 - Ymax => 35x106 X 87.5 22774471.71 Tmax = 134.47 MPa Shece storess due to load Pn will be! va It v (R3-R) TER"-R;"] [Ro-Ri] 4 X 40 5x103 x (7.53 - 01:53) 37 [ 87.5"-1.54] [97.5 - 81.5] T= 25.40 5 MP Hence Tmax for point H : Emax = 134.47 + 25.405 Emax = 159.87 Н MPa b) Ulven, internal press we = 3600 kPa Sheco storess due to internal pressure will be Gmax 3.6X163 4t 4x6 = 24.45 MPa

Tmax = Shear Storess due to py: v (Ro3 –R; 3) TC Rot-Ri4] [ Ro-Ri] 4 X 68.5x103x 87.53-81.53) 37 C 87.54. 01.54) C 87.5 - 81.5) U Tmax = 42.96 MPa Thus, Tmax at point k will be -- Tmax 24.45+ 42.96 Tmax - 67.41 MPa ::