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If the design of a solid shaft based on the maximum-distortion-energy leads to 6 C= (4M2...
as soon as possible If the design of a solid shaft based on the maximum-distortion-energy leads...
as soon as possible
If the design of a solid shaft based on the maximum-distortion-energy leads to c (AMP® +37° where is the radius of the shaft, Mis the applied moment and is the applied torque. Calculate the minimum diameter of the shaft below in in to 2 decimal places, i allow77ksi. B -0.5 ft 3 ft -0.5 ft -2 ft 300 lb 120 lb 300 lb 120 lb
D Question 9 3 pts If the design of a solid shaft based on the maximum-distortion-energy...
D Question 9 3 pts If the design of a solid shaft based on the maximum-distortion-energy leads to c= ( (111 +370) :) ) where c is the radius of the shaft, Mis the applied moment and T is the applied torque. Calculate the minimum diameter of the shaft below in mm to 2 decimal places, if O allow = 142 MPa. 100 mm 500 N 150 mm 200 mm 500 N 150 mm 100 mm
A solid 1.50-in.-diameter brass [G = 6600 ksi] shaft (2) has been stiffened between A and...
A solid 1.50-in.-diameter brass [G = 6600 ksi] shaft (2) has been stiffened between A and B by the addition of an aluminum-alloy tube (1). The tube has an outside diameter of D1 2.50 in., a wall thickness of t10.10 in., a length of L 12 in., and a shear modulus of G- 3900 ksi. The tube is attached to the brass shaft by means of rigid flanges welded to the tube and to the shaft. (The thickness of the...
A solid shaft 32 inches long must carry a torque of 5600 lb-in. The shaft is...
A solid shaft 32 inches long must carry a torque of 5600 lb-in. The shaft is made out of aluminum. Aluminum shafts come in increments of 1/16th inch increments between diameter of 0.25 and 2.5 inches. Determine: a) the required size and cost of an aluminum shaft based on the below design criteria. Allow Shear Stress (ksi) Allow Angle of Twist (deg.) Density (lb/ft3) Cost per Pound ($) Modulus of Rigidity (ksi) Aluminum 18 4.5 169 0.75 4000 Design...
ta. (25 points) Using an allowable shearing stress of 5 ksi, design a solid shaft that...
ta. (25 points) Using an allowable shearing stress of 5 ksi, design a solid shaft that can transmit a 12 hp at a speed of 1800 rpm. Note(1) : Power -2 fT where f is frequeney (Cycles/second) and T is torque (in-b) Note(2): 1hp 550 ft-lb-6600 in-lb
5 Section 2 Problem 5 (25 pts.) A solid shaft 32 inches long must carry a...
5 Section 2 Problem 5 (25 pts.) A solid shaft 32 inches long must carry a torque of 3600 lb-in. The shaft is made out of aluminum. Aluminum Shafts come in increments of 1/16th inch increments between diameter of 0.25 and 2.5 inches. Determine: a) the required size and cost of an aluminum shaft based on the below design criteria. 02:55:27 Allow Shear Stress (ksi) Allow Angle of Density Cost per Modulus of Pound Rigidity ($) (ksi) Twist (deg.) Kib/A3)...
A solid steel shaft is loaded as shown while transmitting rotational power between two pulleys. Pulleys...
A solid steel shaft is loaded as shown while transmitting
rotational power between two pulleys. Pulleys at points C and D
measure 5 inches and 7.5 inches in radius, respectively. Calculate
the minimum shaft diameter for a safety factor of 2.0 based on the
Maximum Distortion Energy failure theory. Yield strength = 100
ksi.
5 inches 300 N 0.250 m 200 N 550 N 0.250 m 400 N 0.150 m D 7.5 inches
Section 2 Problem 5 (25 pts.) A solid shaft 32 inches long must carry a torque...
Section 2 Problem 5 (25 pts.) A solid shaft 32 inches long must carry a torque of 4800 lb-in. The shaft is made out of aluminum. Aluminum shafts come in increments of 1/16th inch increments between diameter of 0.25 and 2.5 inches. Determine: a) the required size and cost of an aluminum shaft based on the below design criteria. Cost per Allow Shear Stress kksi) Allow Angle Density of Twist (deg.) (1/A3) Pound Modulus of Rigidity (ksi) Aluminum 18 4.5...
design a shaft to transmit a load based on B106.1 which is attached Design a shaft...
design a shaft to transmit a load based on B106.1 which is
attached
Design a shaft to transmit a load based on ANSI/ASME Standard B106.IM-1985 (40 points) a) Identify which loading case this analysis can be applied to and why: Case i) T. -9 kNm, T, -0,M.-0, M.-6.5 kNm, kr 1.57, n = 2 Case ii) T. - 7 kNm, T.-0, M -8 kNm, M-6 kNm, k-1.57, n-2 b) Perform the design and calculation on the acceptable case with: i)...
Pulley Diameter = 800 mm Base Plate Diameter = 1200 mm Shaft Mounted Wheel Axial force...
Pulley Diameter = 800 mm Base Plate Diameter = 1200 mm Shaft Mounted Wheel Axial force F2 along the shaft axis Belt connected to motor with tension force F Figure 1. Side View Belt Bearing A. Bearing B FR = 2 kN --- - - - - - - - - - - > ---- 500 mm 500 mm 500 mm F1 = 500 N 'Fw = 1 kN Figure 2. The design of a fatigue test machine for car...
as soon as possible
If the design of a solid shaft based on the maximum-distortion-energy leads to c (AMP® +37° where is the radius of the shaft, Mis the applied moment and is the applied torque. Calculate the minimum diameter of the shaft below in in to 2 decimal places, i allow77ksi. B -0.5 ft 3 ft -0.5 ft -2 ft 300 lb 120 lb 300 lb 120 lb
D Question 9 3 pts If the design of a solid shaft based on the maximum-distortion-energy leads to c= ( (111 +370) :) ) where c is the radius of the shaft, Mis the applied moment and T is the applied torque. Calculate the minimum diameter of the shaft below in mm to 2 decimal places, if O allow = 142 MPa. 100 mm 500 N 150 mm 200 mm 500 N 150 mm 100 mm
A solid 1.50-in.-diameter brass [G = 6600 ksi] shaft (2) has been stiffened between A and B by the addition of an aluminum-alloy tube (1). The tube has an outside diameter of D1 2.50 in., a wall thickness of t10.10 in., a length of L 12 in., and a shear modulus of G- 3900 ksi. The tube is attached to the brass shaft by means of rigid flanges welded to the tube and to the shaft. (The thickness of the...
ta. (25 points) Using an allowable shearing stress of 5 ksi, design a solid shaft that can transmit a 12 hp at a speed of 1800 rpm. Note(1) : Power -2 fT where f is frequeney (Cycles/second) and T is torque (in-b) Note(2): 1hp 550 ft-lb-6600 in-lb
5 Section 2 Problem 5 (25 pts.) A solid shaft 32 inches long must carry a torque of 3600 lb-in. The shaft is made out of aluminum. Aluminum Shafts come in increments of 1/16th inch increments between diameter of 0.25 and 2.5 inches. Determine: a) the required size and cost of an aluminum shaft based on the below design criteria. 02:55:27 Allow Shear Stress (ksi) Allow Angle of Density Cost per Modulus of Pound Rigidity ($) (ksi) Twist (deg.) Kib/A3)...
A solid steel shaft is loaded as shown while transmitting
rotational power between two pulleys. Pulleys at points C and D
measure 5 inches and 7.5 inches in radius, respectively. Calculate
the minimum shaft diameter for a safety factor of 2.0 based on the
Maximum Distortion Energy failure theory. Yield strength = 100
ksi.
5 inches 300 N 0.250 m 200 N 550 N 0.250 m 400 N 0.150 m D 7.5 inches
Section 2 Problem 5 (25 pts.) A solid shaft 32 inches long must carry a torque of 4800 lb-in. The shaft is made out of aluminum. Aluminum shafts come in increments of 1/16th inch increments between diameter of 0.25 and 2.5 inches. Determine: a) the required size and cost of an aluminum shaft based on the below design criteria. Cost per Allow Shear Stress kksi) Allow Angle Density of Twist (deg.) (1/A3) Pound Modulus of Rigidity (ksi) Aluminum 18 4.5...
design a shaft to transmit a load based on B106.1 which is
attached
Design a shaft to transmit a load based on ANSI/ASME Standard B106.IM-1985 (40 points) a) Identify which loading case this analysis can be applied to and why: Case i) T. -9 kNm, T, -0,M.-0, M.-6.5 kNm, kr 1.57, n = 2 Case ii) T. - 7 kNm, T.-0, M -8 kNm, M-6 kNm, k-1.57, n-2 b) Perform the design and calculation on the acceptable case with: i)...
Pulley Diameter = 800 mm Base Plate Diameter = 1200 mm Shaft Mounted Wheel Axial force F2 along the shaft axis Belt connected to motor with tension force F Figure 1. Side View Belt Bearing A. Bearing B FR = 2 kN --- - - - - - - - - - - > ---- 500 mm 500 mm 500 mm F1 = 500 N 'Fw = 1 kN Figure 2. The design of a fatigue test machine for car...
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