You have prepared a solution by dissolving 254.61mg of copper(II) nitrate pentahydrate in 1.25kg of water. What is this solution's Cu+2 concentration in parts per million, ppm?
ppm is parts per million.
1 ppm = 1 mg of solute in1 L of solution .
or
1 ppm = 1 mg of solute in 1 kg of solution [ 1 L = 1000 ml = 1000 g , d = 1g/ml]
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Given 254.61 mg of copper(II) nitrate pentahydrate in 1.25 kg of water.
Molar mass of Cu(NO3)2.5H2O = 232.6 g/mol
Number of moles in 254.61 mg of Cu(NO3)2.5H2O = mass /MW
= (254.61 mg /232.6 g/mol*1000)
= 0.0010946 moles
Therefore ,
0.0010946 moles of Cu(NO3)2.5H2O = 0.0010946 moles of Cu^2+ ion
SO mass of 0.0010946 moles of copper ion = moles * Atomic mass of Cu
= 0.0010946 moles * 63.55 g/mol
=0.06956 g of copper ion
So 0.06956 g of copper ion present in 1.25 kg of water.
OR
69.56 mg of copper ion present in 1.25 kg of water
mass of copper ion present in 1 kg of water = 69.56 mg / 1.25 kg
= 55.65 mg / Kg
So it is expressed in ppm as 55.65 ppm
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