Question

Guess what. It turns out that the Mars/M&M candy company has been hiding a dark secret. It turns out that the M&M is not made in a factory. THEY REPRODUCE IN THE WILD! Oh the humanity, have we no shame as we gobble down all that rich chocolate goodness, joyous as we crunch their candy shells (or are they carapaces) into goo, happy in the fact that our hands will not be stained by the evidence of the cocoa-colored carnage. And not only are they being trapped and bagged; they are also being BRED! Behind their façade, these nougat-laden vipers force wild type black and colorless white M&Ms (that do not express any of the three LINKED color genes) to do the nasty only to rear offspring for munching. The F2 generated from crossing two black F1 progeny yielded the distribution seen below. From this information map the three color genes. Then eat a carrot, you chocoholic bastards. 199 14 66 736 m 212 m 71 11 m 784

Answer 1

Suppose, color Genes are a,b,c

and wild type Genes are +,+,+

We know highest number of progeny represents parental phenotype. Lowest number of progeny represents double crossover phenotype.

m 199 S.C.0.1 m 14 D.C.O. m 66 S.C.0.11 m 736 Parental m 212 S.C.0.1 m 71 S.C.0.11 11 D.C.O m 784 Parental

Distance between a e 199+ 212 +66+7) 2093 는 X 100 = 26.! ♡ or 26 map unit Distance between a b 199 +212 x 100 = 19.6 map 2093 unit Distance between be 66 +7l x 100 = 65 2093 map unit

19.6สสา 6.Sทน b 26:[V1-3