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47 mL of 0.02M of HCl is used to titrate 25mL of Ca(OH)2. a) What is...

47 mL of 0.02M of HCl is used to titrate 25mL of Ca(OH)2.

a) What is the molarity of the hydrochloric acid?

b) What is the molarity of the hydroxide ions in the Ca(OH)2?

c) Calculate the solubility product from the titration. Answer needs to be written using Engineering notation, where 3.14 x 10-5 = 3.14E-5.

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Answer #1

=> (a) nolarity of HCl wed. - molarity is ooah, -) moles of Hel wied is a molarity x volume -> 00an), * 41x16x 9.44154 moles.

Dear student can you precise the question c for solubility product calculation!!

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