Question

5. (10pts) the 4-mm-diameter cable BC is made of a steel with E = 200 GPa as shown in Fig. 2. Knowing that the maximum stress in the cable must not exceed 190MPa and that the elongation of the cable must not exceed 6 mm, find the maximum load P that can be applied.

Answer 1

In this two conditions are taken.

1).cable elongation

2). Max allowable stress

Given .. Diameter cable d umm 3 - 200 X10 N/mm 200 X10 N/m 7 E = 200 G pa Maximum stren in the cable 190 MPa Imax sl < bmm. 2.5m length of the cable (e) e pa (6)"+ (u) la 3.5m 52 l um 190 MPa max Tmax 190 MPa A Xma 190 x ex () NI most T, max v Т. 2.387 KN max

in the Cable By using Elongation model Trimite pl 8- Sl AE . - Trimit (81). A. E e. units 3 n 1 x (4)". 200x10 6. mon. no Nima Imm T. limit (152) x 1000 mm 2.091 KN 2) IT limit From 0 { we hare to consider only. Trimit T limit satifier both the conditions Max allowable stoen and Elongation = T TE 2.091 KN limit

Load P Maximum 16? can be appiled B 4 6 ran' (4) Fano = Tcoso 2.5m| ANT Tsino O = 33.699 p 3.5m A A um. Consider moment at EMA = 0 ( x 3.5) (1 x sino) x 6 3 p = 2.091 X10 X sin ( 33.69) x6 3.5 p: 1.9883 KN