Question

Light of wavelength 700 nm falls on a 0.44 mm wide slit and forms a diffraction pattern on a screen 1.2 m wway. (a) Find the position of the first dark band on each side of the central maximum. mm (b) Find the width of the central maximum. 3. [-/10 Points] DETAILS SERCP7 24.P.031. MY NOTES PRACTICE ANOTHER Light of wavelength 587.9 nm illuminates a siit, of width 0.74 mm. (a) At what distance from the slit should a screen be placed if the first minimum in the diffraction pattern is to be 0.05 mm from the central maximum? (b) Calculate the width of the central maximum mm MY NOTES PRACTICE ANOTHER 2. [-/10 Points) DETAILS SERCP7 24.P.033. A sit of width 0.65 mm is illuminated with light of wavelength 460 nm, and a screen is placed 112 cm in front of the sit. Find the width of the first and secondaima on each side of the central maximum W mm (1st maxima) W2 mm (2nd maxima)

Answer 1

587.9 x 10 9 1 ) 2704.54 x 10-6 a=700nm slit width , az 0.44 mm distance of screen, De 1.7 m a) Position of first dank band, n=0x 1.7 x 700x169 0.448103 az 2.7 mm a x z b) Width of central maxima , = 2D7 2 i 2.7 mm elsoumm ☺ १ ) x=587.9mm az 0.74 mm a) NI 0088mm 22 0.88x103 0.74*10-8 ах 2 2 D z lollx10 3 x 103 m D .l.ilm ✓ 2 9 b) width of central massima = 207 2xl'llx587.9x109 0.74x10-3 21.76mm/u

3 ) 2 ubonm z 2 2 of menima W, z AD 2 a Position of IT rd az 0.65 mm 112 cm Width Ist maxima Position of second manima - Position of first 200 a W, 460 x 109 x 112 x 10-2 0.65 mm 792.61 x W, a 0.78 nam W, 20.79 mm W₂ minima - Position III minima لیا z AD 2 -6 Wi 2 M of 2 3xD Z 2xD a 2 a Wz 2 0.79 mm 는