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Question 12 6 pts The scores on a certain test are normally distributed with a mean score of 65 and a standard deviation of 2
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Answer #1

Solution:-

=> option A. 0.1587

Explanation :

P(X > 65.2108) = P((X-mean)/(s/sqrt(n)) > (65.2108-65)/(2/sqrt(90))
= P(Z > 0.9999)
= 0.1587

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