Solution:-
=> option A. 0.1587
Explanation :
P(X > 65.2108) = P((X-mean)/(s/sqrt(n)) >
(65.2108-65)/(2/sqrt(90))
= P(Z > 0.9999)
= 0.1587
Question 12 6 pts The scores on a certain test are normally distributed with a mean...
The scores on a certain test are normally distributed with a mean score of 53 and a standard deviation of 2. What is the probability that a sample of 90 students will have a mean score of at least 53.2108? 0.8413 0.3174 0.3413 0.1587
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