Question

10032 100 PM 2.100 COSIOS tv Find the total compler power developed by the source and What complexpower is dissipated by each component

I need help with this one,
thanks

Answer 1

solution: - ot) v given:- cos (1044) Vsit) = V2.100 ✓ Loº v 2x100 (Vs )gms 12 (VS) om 100 LOC v omsa W= 4. 10 rad Dec i 11 100 R - - ca 10 4x 1x10-6 Wc ابريل 104x loox 106 1 r XL = Phasor domain circuito ic Vc 102 ůRI + HE +- - iloon VRI 100 S2 jir VR2 IR 2 VL vs CL Kis b

Grea. Vs is Zeq = 100 x 31 +10 - - yioo (100+10) Zeq 99.504 1-84.226ºr So: lis)oms = (Vsms zea 1100/00 99.504|-84.226 1.0049 (04.22 6 A Ils ons = all components. calculation of Now complese power (Valguns x ( is som Ss oms Ss = 1000 x 100049 -84.226° Ss = (10.109 -99.900'j) VA & compene power delivered by source ar oms (cc)oms = (is) on = 100045 104-226A (ve) oms= (-3700) x (c)gms

(Vc) om sa 1000 gg 1-5.774°W * (Vc)oms x Cicloms (Se) 100049 | -5.7740 x 1.0049 1-844226° Sc = VA -) tom Sc= 0-100198 compeen power absorbed by capacitor 184.226° A CR, - įs= is = 1 100045 WRI goXir, 10X100049 1890226 WRI: 10.049 10402269 SRL = (VRI)oms x ( FR )oms 10.049 184.226 X 1.0049 4-84.226 VA SRI= 10.098 + 1° 0 complen poneer eer absorbed resistorr, by

1.0045 184.226 y si = 0.0100 173.65 XIDO using current division at node IR 2 = IR X (31) (1+100) ( 1+100) (Te 2) (VRI)emsa (JP2) minst 100 0.0100 (173-650 A oms (UR2){ms= 1.0048 (173065°v (SR2) (VR2)ems x (IR2Je 100048 1173.65 x 0.0100 (-173-65° SR2 = 0.0100 + 50 VAI complen power absorbed by Ress's for R2 on (VL) emsa (VR2 Dem se 100048 1173.65'v (NL) ems ji 1.0048 1730850 TI (Il Semsa (IL)pms= 100048 (030650 A X (52) = (VL)ems x (IL) em 1,0048 (173.65°x 100048 6-83.650 SL = compeen poner weer absorbed 0 +1100096 VA inductore SL by