Question

1. For each of the beams shown, find reactions, draw the complete shear force and bending mo ment diagrams, determine the centroid, the moment of inertia and the maximum tensile and compressive stressess. Label all values on you diagrams and include UNITS. 2 kN/m 2 KN 15 kN-m A B с O D 2 m Im 1 m 2 πι 0.5 m 0.05 m 0.6 0.05 m 0.05 m 0.05 m 10 KN 20 KN 1SKN SIN- 10 KN 16 kN. 15 Nm H 2m 2 LE

could you just answer the bottom one please

Answer 1

20 kN/m 15 Kw lokum Skum 10kw/m 16 kNm → A E AB PRO ? F IŠ Kum TRH Im K 2m 2m ima 2m * Applying qulaboom equations EF=0 Ro+Rut 15x2 = 20x2 +IS tlox2 RA+R4 = US KN EMHO 10 + Rexq +15x2x(+5) -20x2x ( + 7) +15x4+5 HG -loxzx { RB - +21 KN | RH=24 KN Sheros Force varbus pants - SF @ Hjust sight SF @ Hleft =-24 kn SF @ G =-24 +10x2 =-4 ku 3-4 kw SF @ Eright Eleft =-4+15 = 11 KN S.F Doight = 11 KN SF a C = 11-15x2 = -19 KN SF @ Bright =-19720x2 21 KN SF Blet = 21-21 -0 SF @ A Bending moments - BM A BM @ B = 10 km BM с = 10 +21X2-20x2xŽ = 12 kwam BM D = 10 +21x4–20x2x(+2)+15xzxź =4 kum BM @ BM O DO E = 10 +21x8-80x2x62 +3) +15x2x(+) = 15 kn-m F =6+21x6-20x2x(+4+15x2x(4+2)-15x1 = || knom fright =1175 -16 kum = 24x2 -16- 10x2xŽ - 12 Ka-m BM BM @ H -916 ku-m Shear force Diagboom 20 krulm lokum lokum 16 kw-m Skum Is kn v E artists NH 24Kw is kolm 21 KN 21 I 10 + O O SED los m -19 3.2667 m -24 21.03 16 IS 12 12 + 10 + BMD - 0.03 -16 Masc. Bending moment M=21.025 kunto (Sagging maz. SF = 24 KN Soo mm centooid bo mm a, q=100x400 y = = 4000 -200 mm ! Az = 500x100 uco mn Iz zubot 100-450 mm A- Toomm 100 mm ỹ 40000x200x2 +500xbox450 130000 9 =296.153 m Moment of inertia I = E(Ex, C6, +AB) Pasallel ax's thessem x[ 1532] boxyoo I = 2x/ +40ooox(200-296.153 12 + sooxico +50CCOX 12 650-296 Ixx = 3.031x109 mm mare compressive stress fs F.Ch-y) f 21.025 x 106 3.031X109 -x (500-296.153) f=1.414 maal Comp max tensile stress f=. f 21.028xot X296.53 3.031 x09 frens = 2.05 mpal Scanned with CamScanner

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