A random sample of 61 fifth grade students was selected and given the Stanford-Binet IQ test....
The Stanford-Binet Intelligence Scale is an intelligence test, which, like many other IQ tests, is standardized in order to have a normal distribution with a mean of 100 and a standard deviation of 15 points. As an early intervention effort, a school psychologist wants to estimate the average score on the Stanford-Binet Intelligence Scale for all students with a specific type of learning disorder using a simple random sample of 36 students with the disorder. Determine the margin of error,...
a random sample of 150 students has a grade point average with a mean of 2.86. Assume the population standard deviation is 0.78. Constrict the confidence interval for the population mean ų, if c=0.98. 2.51, 3.53 2.31, 3.88 2.43, 3.79 2.71, 3.01
A random sample of size 90 is selected from a population of over 2,000 students. The sample is measured on an achievement test and the mean score on the test is 79.5. The difference between the sample mean and the population mean is due to: sampling bias sampling error the sampling fraction sampling stratification Sampling bias is variation caused by random fluctuation. True False
Suppose a new standardized test is given to 98 randomly selected third-grade students in New Jersey. The sample average score Y on the test is 57 points, and the sample standard deviation, sy, is 10 points. The authors plan to administer the test to all third-grade students in New Jersey. The 95% confidence interval for the mean score of all New Jersey third graders is ( 55.02, 58.98 ). (Round your responses to two decimal places.) Suppose the same test...
13. +-6.66 points WaneFMAC7 9.5.033. My Notes IQ scores (as measured by the Stanford-Binet intelligence test) in a certain country are normally distributed with a mean of 100 and a standard deviation of 11. Find the approximate number of people in the country (assuming a total population of 323,000,000) with an IQ higher than 120. (Round your answer to the nearest hundred thousand.) people 14. 0/6.66 points | Previous Answers My Notes This exercise uses the normal probability density function...
#3 One of the most common ways of measuring intelligence is the IQ test. IQ scores in the US population have an average of µ = 100 and a standard deviation of σ = 15. Suppose a researcher wanted to test whether socioeconomic status (SES) has an effect on IQ scores. The researcher takes a random sample of n = 100 people, selected from a list of the 1000 richest people in the United States. a. Based on this information,...
An IQ test is designed so that the mean is 100 and the standard deviation is 13 for the population of normal adults. Find the sample size necessary to estimate the mean IQ score of statistics students such that it can be said with 90% confidence that the sample mean is within 4 IQ points of the true mean. Assume that σ=13 and determine the required sample size using technology. Then determine if this is a reasonable sample size for...
A random sample of 86 eighth grade students' scores on a national mathematics assessment test has a mean score of 275. This test result prompts a state school administrator to declare that the mean score for the state's eighth graders on this exam is more than 270. Assume that the population standard deviation is 33. At alpha=0.05, is there enough evidence to support the administrator's claim? Complete parts (a) through (e). (a) Write the claim mathematically and identify H0 and...
2. Suppose that a random sample of 41 state college students is asked to measure the length of their right foot in centimeters. A 90% confidence interval for the mean foot length for students at this university turns out to be (21.709, 25.091). If we now calculated a 95% confidence interval, would the new confidence interval be wider than or narrower than or the same as the original? b. Suppose two researchers want to estimate the proportion of American college...
A sample of 36 randomly selected students has a mean test score of 83.4 with a standard deviation of 8.92. Assume the population has a normal distribution. Find the margin of error, and then find the 95% confidence interval for the population mean.