A sample of 36 randomly selected students has a mean test score of 83.4 with a...
A sample of 36 randomly selected students has a mean test score of 83.4 with a standard deviation of 8.92. Assume the population has a normal distribution.
Find the margin of error, and then find the 95% confidence interval for the population mean.
Homework Answers
df =n -1 = 36 - 1 = 35
From T table,
t critical value at 0.05 significance level with 35 df = 2.030
Margin of error = t * S / sqrt(n)
= 2.030 * 8.92 / sqrt( 36)
= 3.018
95% confidence interval for 
is
- E <
<
+ E
83.4 - 3.018 <
< 83.4 + 3.018
80.382 <
< 86.418
95% CI is ( 80.382 , 86.418 )
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