Question

The interfacial conductance for ceramic is hc=5000W/m^2-k

Incorrect Question 2 0/33 pts FIT 5 T An iron pipe is covered by ceramic insulation. The inner radius, ri of the metal pipe is equal to 0.05 m. while its outer radius, rc, is equal to 0.09 m. On the other hand, the ceramic insulation has a thickness of 0.04 m. If the inner and outer temperatures, Ti and To, are kept constant at 384 K and 341 K, respectively, find Te in Kelvin. The length of the pipe is 10 m. Consider contact resistance between the ceramic and the iron. [use 2 decimal places when rounding off] 372.06

Answer 1

Ang. ion Pipe ceramic insulation. co Kiront let alsume 63 W/mik Kceramic = 20 w/mik interfacial Conductance hc=5000 W/m²K. NOW ceramic due to hc Contact Temp drop Tee & Tcz between ison & in contact so Two ose thise. Given :- ri= 0.04 m, l=lom ro= olm = 0.04 m (t) thickness of insulation 01-004 rc = rot = rc = 0.06m Ti= uook To = 323K

Now for To, :- Ti-To Ti - Ta en/re enforc | yo rc + LA 27 Kironel 27 kcal 22 Kirupid Here A=2 Trol 27 (0.ou) (10) = 2.5132 m2 400 - 323 yoo- Tal In/006 Looy en loos) 0 1 0.06 en/0.06 + 0:04 + (5000) (2-5132) 26X20 X10 27 (60) (10) 22 (60) 10) 77 yoo- Tch 0.00 olo8 +0.000079 + 0.000406 0.000108 400- TCI 77 0.0005835 0.000108 yoo - Tol - 14.01 Tct = 385.98 k Ang.

3 Now for Tc2 :- Ti-Tcz Ti - Tci en content 2a Kironil + he.A 27 Kisonil 400 - 385.98 400- Tez = 0.000108 + 0.000079 0.000108 129814.81481 40o- Tcz - {atrand Calculacan 0.000187 Your TC2 = 24.275 Tc2 = 375.72K Tai = 385.98K & Tcz = 375.72 K 385.98+375.72 Tc= Toit Tcz 2 2 To = 380.85K Ars://