Question

1- Determine the shear and moment at point C for the beam shown in the figure. 6KN/M . VYA FORORD GKN.m fim 1,5m 3m 3 3m

Answer 1

Solution we 6x6 2 = /86N 6 kN/m How 2 m? A o Centroid of Triangle from RA - 7KN/ B GkN-m/ "RB=1 kN 1 l5m port B, 2m 3 m. IL aut 3m Finding of Reactions (RA & RB): (Conversion, while taking moment, Clockwise moment the Articlockwise moment - oment --ve Taking Moment @ B, E MB = 0, > - [18*4-097-63+(Raxb)-a 36 + 6 = 6 Ra A2 GRA .RA = 7kN We know that, Total downward load and } = { Tot Total upewand lood & RA +RB 18AN 7+ RB 18kN .. Ro=11 kN • Finding Shear force @ point co Considering left of the part pont C, the Shear force is, SFC +7- I (1843) 2 7-27 :: SFC -20 kN

is, Finding Bending Moment @ Pont co Corsidewing left of the point c, the BM @ pont ļ (1873) x(5-3) I distance BMc +(773) 21 - 27 BMC -6 kN-m RESULT: At point " Shear Force - 20 KN Bending Moment - 6 kN-m +ve - ve Moment Force x perpendicular distance, - While calculating Berding moment, the sign conrensin followed is, Sagging moment taken as Hogging moment taken as, Note: While calculating Shear force & Bending moment, either left side of the the right of a section, for a required point Here in this problem, I have taken deft side of point'? Because, for easier calculations. Note that consider right side, will always get the section or we can consider We if we same ariswer.

At point C,

Shear force= -20kN

Bending moment= -6kNm

While calculating shear force and bending moment, we can consider either left or right of the section .

Here, I have taken left side of point C, for easier calculations. If we consider right side , we will get the same answer.. but to avoid tedious calculations (bcz of trapezoidal shape) I considered left side of point C.