Question

Please help, I have tried the formula over and over and I just don't know if I am typing it in wrong or what. I know the formula and everything but cannot get the correct answer.

Your answer is partially correct. A very long, hollow cylinder (radius 3.5cm) is formed by rolling up a thin sheet of copper. Electric charges flow along the copper sheet parallel to the axis of the cylinder. The arrangement is, in effect, a hollow tube of current 3.8A. Use Ampère's law to find the magnetic field (a) outside the cylinder at a distance 8.0cm from the axis and (b) inside the cylinder at a distance 2.4cm from the axis. (Hint: For closed paths, use circles perpendicular to and centered on the axis of the cylinder.) (a) Number i 4.34E-7 Units T (b) Number 0 Units T e Textbook and Media Save for Later Attempts: unlimited Submit Answer

Answer 1

Ans. 2 23.5 x10 m Radius of hollow cylinder R = 3.5cm Current in the cylinder I = 3.8 A outside the cylinder at a distance 8810² in from the axis. ca) go= 8em P Ampere loop b I R Apply Ampere's cimenital law, boode = Moi B dleosoo - to I 3 B dal = los 2) BX 280 = xol → B 200 ATX10 X 3.8 M=40 27X88102 *B 9.5 8106 T. Magnetic field outside the cylinder is 9.58l0bg کمال S ( Inside the cylinder at a distance go = 204 em = 2.4x102 m. - Ampere Rufa Love Magnetic field inside the hollow eylinder is because no current is enclosed by the Ampera look. Zero