Question

I don't know what i got wrong in these. Please help, thanks!

Suppose that x2y3 - cosy - 1. Find dy/dx. dy/dx- Enviar Respuesta Incorrecto. Tries 2/5 Intentos Anteriores This discussion is closed

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Answer 1

1.

$x^2y^3-\cos y=1$

$2xy^3+3x^2y^2\frac {dy}{dx}+\sin y\frac {dy}{dx}=0$

$\frac {dy}{dx}=-\frac {2xy^3}{3x^2y^2+\sin y}$

2.

$x(t)=x_1-x_2=10t^2-26t+28$

$\frac {dx(t)}{dt}=20t-26$

$\frac {dx(t)}{dt}=20t-26=0$

$\Rightarrow t=1.3\: s$

$\frac {d^2x(t)}{dt^2}=20>0$

$x_2(t=1.3\: s)= 16.2$

3.

(i) The magnitude of S is less than H

(ii) Since H is perpendicular to Y, H dot Y is zero.

(iii) It is less than zero.

(iv) Since S and Z are parallel to each other, their cross product is zero.

(v) Greater than zero.

(vi) It is less than zero since the angle between R and Z is obtuse.