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Q31 CH4 + 2O2 CO, +2 H2O 100 mole of methane is bumed with 420 mole of air as the above reaction, if the consumed oxygen is 1

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solia CH4 + aor qor cort 2H2O feedia 100 mole. CH4 &. 420 mole of air Air = 81% or +79% Ny = 21x420 79 x 420 100 loo 88.2 mol% conversion of CH4 Cty consumed CHu fed X100 30335 15.625 x loo 100 15.625% 31.2 § X100 % Cesiversion of an 88.2 느 35.43% boOutlet gas composition. 15.625 &cor X100 32 520 2 31.25 x 100 = 67: 520 actu 84.375 X100 16.22% 520 x - 56.95 520 x 100 = 10.

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