(#1 continued) 16.05 g mole 44.01 g mole CH4 202-CO2 2 H:0+802.3 k 200 gmole15.02 gme...

Question

Question

(#1 continued) 16.05 g mole 44.01 g mole CH4 202-CO2 2 H:0+802.3 k 200 gmole15.02 gme c. How many grams of water are produced

Add a comment Improve this question Transcribed image text

Answer 1

Answer #1

+10 molay mas0 6 qmal 14-8 , m ho.ofmolt 94%.豊tmd4 1sb mole 1S 6 4.8 0 1.0 c amemt o H0IS.LX18-02 Q81, 112 = limiting Mngmt:

Add a comment

Answer 2

Similar Homework Help Questions

Consider the combustion of methane: CH4 (g) + 2 02 (g) → CO2 (g) + 2...

Consider the combustion of methane: CH4 (g) + 2 02 (g) → CO2 (g) + 2 H2O (g) If 5.00 g of CH4 burns in the presence of 10.0 g O2, determine the limiting reactant and how many grams of CO2 are produced.
The following data were obtained for the reaction of methane with oxygen: CH4(g) + 202(g) CO2(g)...

The following data were obtained for the reaction of methane with oxygen: CH4(g) + 202(g) CO2(g) + 2H20(1) → time(min)[CH4l (mol/L) 0 10 20 30 0.050 0.030 0.020 0.015 0.020 a) How many moles of CO2 are produced for each mole of CH4 that is used up? b) What concentration of CH4 is used up after 10 minutes? c) What is the concentration of carbon dioxide produced after 20 minutes? d) Write an equation for reaction rate in terms of...
balance Q31 CH4 + 2O2 CO, +2 H2O 100 mole of methane is bumed with 420...

balance Q31 CH4 + 2O2 CO, +2 H2O 100 mole of methane is bumed with 420 mole of air as the above reaction, if the consumed oxygen is 1000 g, calculate : 1- The limiting & excess reactants 2 - The excess percentage 3- Extent of reaction 4 - Conversion percentage of each reactant 5- The outlet gas composition (25 marks)

The thermochemical equation of combustion of methane is: CH4(g) + 2O2(g) → CO2(g) + 2 H2O(l)

The thermochemical equation of combustion of methane is: CH4(g) + 2O2(g) → CO2(g) + 2 H2O(l) ΔΗ =-890.3 kJ 1. Calculate the AH when 5.00 g CH4 react with excess of oxygen. 2. Calculate AH when 2L CH4 at 49 °C and 782 mmHg react with an excess of oxygen 3. Calculate AH when 2L CH4 react with L O2 in a reaction vessel kept at 49 °C and 782 mmHg.
Consider the following reaction. CH4(g) + 2 O2(g) - CO2(g) + 2 H20(1) AH = -891...

Consider the following reaction. CH4(g) + 2 O2(g) - CO2(g) + 2 H20(1) AH = -891 kJ Calculate the enthalpy change for each of the following cases. (a) 2.00 g methane is burned in excess oxygen. Гk (b) 2.00 x 103 L methane gas at 743 torr and 25°C is burned in excess oxygen.
From the following balanced equation, H₂ = 1.0144 CH4 () +202) - CO2(g) + 2 H2O(8)...

From the following balanced equation, H₂ = 1.0144 CH4 () +202) - CO2(g) + 2 H2O(8) How many grams of H20 can be formed when 1.25 g CH are combined with 6.66 g0,?

Here are four different comments: (1) C (s) + H2 (g) => CH4 (g) (2) C2H6...

Here are four different comments: (1) C (s) + H2 (g) => CH4 (g) (2) C2H6 (g) + O2 (g) => CO2 (g) + H2O (l) (3) C (s) + O2 (g) => CO2 (g) (4) H2 (g) + O2 (g) => H2O (l) A. Formulate a methane fire reaction (CH4) according to the given reactions, note that not all reactions are balanced and unnecessary Use all responses. B. What is the theoretical amount of water you will get from...
For question 2, the initial amount of O2 is 2 and of CH4 is 1. This...

For question 2, the initial amount of O2 is 2 and of CH4 is 1. This what I believe it is honestly not completly sure due to the fac that this is all information I can. Please just try your best with the information adviliable. Question 1 An unknown chemical compound has the four elements with the following percent compositions. Carbon: 48.00% Hydrogen: 8.00% Oxygen: 16.00% Nitrogen: 28.00% A Determine the Empirical Formula. B. If the molar mass of this...
The heater in a house burns natural gas with x% excess air according to the reaction: CH4 2 02>CO2 2 H2O The flue gas leaves the burner at Tout. The air and the natural gas (CH4) enter the burner...

The heater in a house burns natural gas with x% excess air according to the reaction: CH4 2 02>CO2 2 H2O The flue gas leaves the burner at Tout. The air and the natural gas (CH4) enter the burner Prepare a spreasheet for this system using a basis of one mole of methane feed to deter at standard conditons of 25°C and 1 atm pressure. mine: a) The standard heat for the combustion for the reaction above, b) The required...

1. Moles of Reactant to Mass of Reactant: Identify the iodide ions and ozone in the...

1. Moles of Reactant to Mass of Reactant: Identify the iodide ions and ozone in the balanced chemical equation. Use mole ratio, then convert to grams. A method used by the EPA for determining the ozone concentration in the air is to pass an air sample through a bubbler containing iodide ions. The iodide ions remove the ozone according to the following reaction: O3(g) + 2 I-(aq) + H2O(l) → O2(g) + I2(aq) + 2 OH-(aq) How many grams of ozone...

(#1 continued) 16.05 g mole 44.01 g mole CH4 202-CO2 2 H:0+802.3 k 200 gmole15.02 gme...

Homework Answers

Add Answer to:
(#1 continued) 16.05 g mole 44.01 g mole CH4 202-CO2 2 H:0+802.3 k 200 gmole15.02 gme...

Post as a guest

Earn Coins

Consider the combustion of methane: CH4 (g) + 2 02 (g) → CO2 (g) + 2...

The following data were obtained for the reaction of methane with oxygen: CH4(g) + 202(g) CO2(g)...

balance Q31 CH4 + 2O2 CO, +2 H2O 100 mole of methane is bumed with 420...

The thermochemical equation of combustion of methane is: CH4(g) + 2O2(g) → CO2(g) + 2 H2O(l)

Consider the following reaction. CH4(g) + 2 O2(g) - CO2(g) + 2 H20(1) AH = -891...

From the following balanced equation, H₂ = 1.0144 CH4 () +202) - CO2(g) + 2 H2O(8)...

Here are four different comments: (1) C (s) + H2 (g) => CH4 (g) (2) C2H6...

For question 2, the initial amount of O2 is 2 and of CH4 is 1. This...

The heater in a house burns natural gas with x% excess air according to the reaction: CH4 2 02>CO2 2 H2O The flue gas leaves the burner at Tout. The air and the natural gas (CH4) enter the burner...

1. Moles of Reactant to Mass of Reactant: Identify the iodide ions and ozone in the...

(#1 continued) 16.05 g mole 44.01 g mole CH4 202-CO2 2 H:0+802.3 k 200 gmole15.02 gme...

Homework Answers

Add Answer to: (#1 continued) 16.05 g mole 44.01 g mole CH4 202-CO2 2 H:0+802.3 k 200 gmole15.02 gme...

Post as a guest

Earn Coins

Add Answer to:
(#1 continued) 16.05 g mole 44.01 g mole CH4 202-CO2 2 H:0+802.3 k 200 gmole15.02 gme...