1. A. The height of a ball above the ground ( in meters) after t seconds is given by h(t) = -4.9t2+4.2t = -4.9[t2- (4.2/4.9)t] = -4.9(t2- 6t/7) = -4.9[t2- 2t *3/7 + (3/7)2] +4.9*(3/7)2= -4.9(t-3/7)2 + 9/10.
This is the vertex form of the equation of a downwards opening parabola with vertex at (3/7,9/10).
B. A graph of the function h(t) = -4.9t2+4.2t is attached. Since the vertex of a downwards opening parabola is its highest point, hence the y -coordinate of the vertex i.e. 9/10 meters is the maximum height attained by the ball. This height is attained 3/7 second after the ball is thrown up.
ht=-4.9t2+4.2t this function Luar1118 auuvily 2. Ivivuuiu v Name Date Show all work or no credit...
Show all work or no credit will be given. 1. The height of a ball (in meters) above the ground after t seconds is modeled by the following function: h(t) = -4.9t2 + 4.2t A) Find the vertex of the function. B) Explain what each coordinate means in terms of the graph.
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please show work! 9. A 2-kg ball is dropped out of a w is dropped out of a window from a height of 12 meters (Point A). It hits the grow and bounces back up to a height of 8 meters above the ground (Point). a. What is the potential energy of the ball at points A and C b. What is the velocity of the ball just before and just after it hits the ground (points B and B')?...