1.The answer is option A
The klinefelter and Turner syndrome are sex linked genetic diseases.In klinefelter syndrome,there is an extra copy of X chromosome and as a result the sex of the individual will be male but will have female sexual characters like gynecomastia,reduced musculature,infertility and small testicles and under developed secondary sexual characters.In turner syndrome,a pair of X chromosome will be missing and as a result,the female will have short stature,nin-functioning ovaries etc..
2.The answer is option B
The pseudosomal regions are the regions that are homologous in the X and Y sex chromosomes.They are involved in the process of pairing of sex chromosomes,recombination of sex chromosomes.They also plays a major role in the proper seggregation of chromosomes during meiosis.
3. The answer is optionB
Since the cell has 3 X chromosomes,the number of barr bodies will be 2
In a cell, the number of bar boies can be calculated by subtracting 1 from the total number of X chroosomes in the cell.The barr bodies are small structures that are seen densely stained in the females.It is made up of inactivated X chromosomes,which are later condensed
Klinefelter syndrome (47, XXY) and Turner syndrome (45, X) are due to View Available Hint(s) O...
Q1. Klinefelter syndrome (47, XXY) and Turner syndrome (45, X) are due to __________. A. improper segregation of autosomes during mitosis B. improper segregation of sex chromosomes during mitosis C. improper segregation of autosomes during meiosis D. improper segregation of sex chromosomes during meiosis Q2. Sex determination and sexual differentiation is controlled by A. the homogametic sex B. sex chromosomes C. homologous chromosomes D. genetic information on autosomes
aluminum Express your answer to two significant figures. View Available Hint(s) I ALO * O a ? Te = Submit Part D water Express your answer to two significant figures. View Available Hint(s) 0 ADD O2 ? T: - Submit Exercise 7.49 - Enhanced - with Feedback and Hints A Revi MISSED THIS? Read Section 7.3 (Pages 267 - 272); Watch KCV 7.3, IWE 7.2. aluminum Suppose that 25 g of each of the following substances is initially at 29.0°C....
Prelecture Reading Question 7.05 Part A Energy cannot be View Available Hint(s) destroyed. o O transferred, transformed, or destroyed. O transferred. Submit Provide Feedback
View Available Hint s) Hint 1. lce vs. liquid waler ven most m a eria í transi inn a ter saw orm from her 1 ad orm hey )ecnme more dense ecause the atoms are morer DSt рак: rd ส s one o the ew e ce hons en ice, orm the rno ecu ees arrange temse ves ri a crysta ne structure with lots of cmpty spacc. This mcans that the samc number of water molcculcs will take up...
Part C Which of the following is an aldohexose? View Available Hint(s) он Н он-с-с-с-ОН он н o ОН ОН ОН Н н-с-с-с-с-с-ОН Η Η Η Η но ОН Н ОН Н О НО-с-с-с-с-с-с-ОН н н ОН н н o ОН Н ОН ОН Н 1 ТТТТІ О н -с-с-с-с-с-с-ОН ІІІІІ Н ОН н н н Submit Part 8 Indicate the charbons Identify the appropriate atoms by selecting each atom and assigning it a map number of 1 until latoms...