Answer is 49.6 percent
Answer is 49.6 percent
Use a table to find the percentage of the area under the standard normal curve between...
q1. Find the area under the Standard Normal Curve in-between z = -0.63 and z = 0.47 Use the Normal table and give answer using 4 decimal places. q2. Find the area under the Standard Normal Curve in-between z = -1.19 and z = 0.36 Use the Normal table and give answer using 4 decimal places. q3. Find P(z < 1.72) Use the Normal table and give answer using 4 decimal places. q4. Find P(z > -2.62) Use the Normal...
Find the area under the standard normal distribution curve to the right of z = 1.57. Use Table E and enter the answer to 4 decimal places. The area to the right of the z value is _______ Find the area under the standard normal distribution curve between z = 0 and z = 2.65. Use Table E and enter the answer to 4 decimal places. The area between the two z values is _______ Find the area under the standard normal distribution curve...
1) Find the area under the standard normal curve to the right of z= -0.62. Round your answer to four decimal places. 2) Find the following probability for the standard normal distribution. Round your answer to four decimal places. P( z < - 1.85) = 3) Obtain the following probability for the standard normal distribution. P(z<-5.43)= 4) Use a table, calculator, or computer to find the specified area under a standard normal curve. Round your answers to 4 decimal places....
12 Find the percent of area under a normal curve between the mean and - 1.12 standard deviations from the mean. (Note that positive indicates above the mean, while negative indicates below the mean.) Click here to see page 1 of the table for areas under the standard normal curve Click here to see page 2 of the table for areas under the standard normal curve. %. The percentage of area under a normal curve between the mean and -1.12...
A.Find the area under the Standard Normal Curve to the left of z = -0.48 Use the Normal table and give answer using 4 decimal places. B. Find the area under the Standard Normal Curve to the right of z = 2.9 Use the Normal table and give answer using 4 decimal places. C. Find the area under the Standard Normal Curve in-between z = -1.86 and z = 0.74 Use the Normal table and give answer using 4 decimal...
Find the indicated area under the standard normal curve. Between z 0 and z = 0.18 5 Click here to view page 1 of the standard normal table. Click here to view page 2 of the standard normal table.6 The area between z 0 and z = 0.1 8 under the standard normal curve is (Round to four decimal places as needed.) L
1. Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to four decimal places.) The area to the left of z = 0 is _______ 2. Sketch the area under the standard normal curve over the indicated interval and find the specified area. (Round your answer to four decimal places.) The area to the left of z = −0.49 is _______ 3. Sketch the area under the standard normal...
Using the TI-84 calculator, find the area under the standard normal curve that lies between the following Z-values. Round the answers to four decimal places. (a) Find the area under the standard normal curve that lies between z=-0.29 and z = 2.26. (b) Find the area under the standard normal curve that lies between 3 = -1.92 and 2 = -1.17. (c) Find the area under the standard normal curve that lies between z = 0.91 and 2 = 1.58....
Find the area under the standard normal curve. Round your answer to four decimal places. (a) Find the area under the standard normal curve to the right of z=−0.78. (b) Find the area under the standard normal curve that lies between z=1.26 and z=2.32. (c) Find the area under the standard normal curve that lies outside the interval between z=−1.93 and z=0.59. (d) Find the area under the standard normal curve to the left of x=−2.08.
Use a table of areas to find the specified area under the standard normal curve. 12) The area that lies between 0 and 3.01 A) 0.4987 B) 0.9987 C) 0.5013 How is A the answer and not B?