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Use a table to find the percentage of the area under the standard normal curve between the two values. Round your answer to t
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Answer is 49.6 percent
2-0,2=-2-62 -2.60 Area = Plosz>-2.62 plo) - P(-2.62) 0,5 0.004396 = 0.495604 Scanned with CamScanner

Answer is 49.6 percent

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