Member | Force(KN) | Nature of force |
DG | 0 | Neutral |
DH | 3 | COMPRESSIVE |
CH | 5.66 | TENSILE |
GH | 4.8 | COMPRESSIVE |
CF | 5.66 | TENSILE |
CG | 3 | COMPRESSIVE |
BG | 5.66 | TENSILE |
GF | 9.6 | COMPRESSIVE |
BE | 5.66 | TENSILE |
BF | 3 | COMPRESSIVE |
AF | 0 | Neutral |
EF | 4.8 | COMPRESSIVE |
AE | 3 | TENSILE |
find all the forces 4 m 4 m 4 m EY EX E F G H 2.5 m D A B С 13 KN 3 kN 3 kN
Can you find all the forces using methods of joint and methods of section? Ex, Ey, Dy, Force EA, Force EF, Force EB, Force FG, Force FB, Force FC, Force GD, Force GC, Force GH, Force HD. Thank you! Question Completion Status: Question 3 10 points What is the force on member FG (KN)? 4 m -4 m 4 m Ey Ex E F G H 2.5 m D A B с [: 13 kN 3 kN 3 kN DY
What is the force on member FG (KN)? -4 m -4 m 4 m EY EX E F G H 2.5 m D A B [: (3 kN 3 kN 3 KN D
Q = 170 kN F = 80kN The x component of the reaction at E,Ex (in kN) The y component of the reaction at E, Ey (in kN) The y component of the reaction at A, Ay (in kN) The force in member ED (in kN) The force in member IB (in kN) The force in member IH (in kN) Question 2 W = 115 lb P = 80 lb The x component of the reaction at H,Hx (in lbs)...
If the member EF was removed and the support at F was replaced as shown below, determine the support forces at E and F 500 lb 500 lb 12 ft 12 ft12 ft 12 ft 15 ft Support force at E, (Ex, Ey). 1 pt] lb (Sign: negative if leftwards or downwards) Support force at F, (Fx, Fy). [1 pt] )lb (Sign: negative if leftwards or downwards) If the member EF was removed and the support at F was replaced...
Example: Determine the forces acting on all members of the frame shown below 4 m 8 m 3 kN E 3 m 5 m 4 kN 2 kN 10 m 5 kN.m 3 kN.m A B 10 m Example: Determine the forces acting on all members of the frame shown below 4 m 8 m 3 kN E 3 m 5 m 4 kN 2 kN 10 m 5 kN.m 3 kN.m A B 10 m
a) 4 Ex (p) = 2 эм all Forces on of MA?) M 12 Exercise Grad Ex(u) = t mr² 3) Graf THEOREM (Work - Kinetic energy The work done by the resultent of the . equal the kinetic energy WE AERE Waz - Ę.la] = - - bez Ext Ex(B) = (A) + W ER (B) > Ex(A) => > ECB) - E. (A) → Voor Ex(B! When W positive so wso Foo so theo ΤΕ > > IF...
Find the forces on each member Z С B D 6 m A E = 17 KN X 6 m 3 m 3 m у
Q1 a) List all the zero force members in the truss below Find Forces in AB, An and MN 2 m B C D E F G H I 2 KN 2 KN 5 KN 3 KN - 16 m, 8 @ 2 m
For the armor shown, determine the forces on the BD and BF members. -4 m-fo4 m--fe-4 m-44 m- A В. C 6 m DC E F G H 20 kN 20 KN 20 KN