Question

Can you find all the forces using methods of joint and methods of section? Ex, Ey, Dy, Force EA, Force EF, Force EB, Force FG, Force FB, Force FC, Force GD, Force GC, Force GH, Force HD. Thank you!

Question Completion Status: Question 3 10 points What is the force on member FG (KN)? 4 m -4 m 4 m Ey Ex E F G H 2.5 m D A B с [: 13 kN 3 kN 3 kN DY

Answer 1

Joint E TEY=6kN tan 2.5 E FEF Ex=0 = 32 Y FBE FAE = 3 kN EFY = 0 FBE sino + 3 = 6 = FBE 5.6612 KN J Ź Fx FEF - FBE cosa E EF 4.8010 KN C - Joint B KEBE FBF FBG E Fx О B FBE Coso = FBG cosa 4.3 kr FBE FBG FBG 5.6612 KN -О . EFY FBF + 2(5.6612 sino = 3 FBF = -3 KN OR FBF = 3 kN

Joint FFG FEF = 4.81010 > FFC FAF FBE = 3 kN EFY = o 3= FFC sino FFC = 5.6612 KN E Fx = 0 . (5.6612 Cos 0) + 4.8010 = FFC FFG 9.602 KN C • Joint C FCH fce E Fx FFC fch = FFC FCH 5.6612 kN T * 3 KN EFY fca + 3 = 2(5.6612) sino fca = = 3 KN С

Cc Joint (9.602 kN) FFG FGH Q Fad Trace FBG = 3kN = 5.6612 KN Ź Fy = 0 FGD 3 = 5.6612 sinot FGD - zero force member E Fx Fur + 5.6612 coso = 9.602 FGH = 4.8010 KN С. • Joint D y FDH EFY - О D FDH - DY - DY For 3 KN C