Question

Provide an appropriate response. Find the critical Fo-value to test the claim that the populations have the same mean. Use a = 0.05. ANOVA Brand 3 nus Brand 1 n=S X-3.0 S=0.50 Brand 2 nas x=26 S=0.60 X-26 S=0.55 2.819 O 1.892 3.47 3.210

Answer 1

population have F F-MSB Here Hotel, = 12 -el Vs Ha: at least one different mean & Analysis of variance Source of Vomation sums of Squares DF Mean Squares SS ICMS) Between SSB = Enj (F; - 7² kal 153 = MSB = SSB kai 115W within SSWE EE CHij -*;)? N-k S'w = Msw=SSW Total SST = Note: ssw = 55. (Hi) - 1;)? We can not use this formula Because individuelle Brandi Brand 2 Brand 3 delta gre not given for each group k= no. of groups=3. n= 8 ng DE 8 N = no. of observations X = 3.0 = 2.6 2.6 = 3x8 =24 S: 0:50 S = 0.60 S=0.55 = not to -2.7333 8 63.0-2.73 12+ 8(2.6-2-737 + 8(2.6–27332 & 2.73 =[0.8536 SSW = 20.5072(8-1) +(0.609%C8-1) + 0.55)C8-4) = 6.3875 source of Sums OF Squares DF Mean Squares F variation SS MS 1.463178 Between SS=0.8536 |3-1=2 s2 - 8536/2 within SSW = 6.3875 24-3-21 SW = 6.3875/21 grond Tola 3 Here SSB = OR22 SST = 241 23 Total to = 5²3 154 E - 0.4268 0.3041666667 1.4031780822) f crinical value = fod, disso, dissn = to 0.05, 2, 21 - 3.4668 = 3.47 to critical value = 3.47 Since to critical value to calculated value 3.47 1.403178082 so we can not reject null hypothesis