Homework Answers
Ans ) 1. Agouti gene
2. Raly gene
3. Raly Promoter
4. Agouti Promoter
The two Genes that is Raly and agouti gene lies next to each
other and they both have their individual promoter
Raly Promoter will drive high gene expression level.
Agouti Promoter is not very active. In wt mice the medium level of
yellow pigment is produced.
Ay mice a yellow mice will undergo deletion mutation and due to
which agouti Promoter and Raly genes get deleted due to which Raly
Promoter is left behind and will drive high Gene expression level
of agouti gene characterized as hypermorphic mutation
Amorphic mutation is one in which no Raly protein is produced by Ay
alleles.
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In the agouti mouse, the gene for coat color is next to the gene which is...
1) Coat color in mice is determined by several independently assorting autosomal genes. Gene A is...
1) Coat color in mice is determined by several independently assorting autosomal genes. Gene A is involved in the distribution of pigment along the hair. A dominant allele (A) produces a hair color called "agouti"--the hair has dark pigment at the base and tip of each hair shaft and yellow pigment in the central portion of the shaft. Homozygous recessive mice (aa) are missing the yellow stripe and thus have solid dark-colored hair. Gene B is involved in the color...
19. Two different gene loci are responsible for determining mouse coat color. A recessive lethal allele...
19. Two different gene loci are responsible for determining mouse coat color. A recessive lethal allele contributing to yellow coat color also exists for one of these two gene loci. The following genotypic and phenotypic information about the mouse coat color alleles is known: (6) Agouti = A-B- • Yellow = AA'B-or A'aB-or A'ab- Lethal (inviable zygote) = A'A- Black = aaB- Albino = -bb a. A cross is made that produces 2 yellow, 1 black, and 3 albino mice....
4. In mice, the Ayallele of agouti is dominant for yellow coat color but is homozygous...
4. In mice, the Ayallele of agouti is dominant for yellow coat color but is homozygous lethal. A yellow mouse, Ay/A, that is also heterozygous for the albino allele, C/c, is crossed to an albino mouse that is also heterozygous for the Ayallele, Ay/A. c/c. What phenotypic ratios do you expect in the progeny? (True or False) a. if these genes are unlinked: 3/8 yellow, 1/8 agouti, 1/2 albino b. if these genes are unlinked: 1/3 yellow, 1/6 agouti, 1/2...
1. At least 3 independently assorting loci are known to govern coat color in mice. The...
1. At least 3 independently assorting loci are known to govern coat color in mice. The genotype C- will allow pigment to be produced by 2 other genes. The cc genotype does not allow pigment production resulting in albino mice. The striped “agouti” hair pattern depends on the genotype A- and the aa genotype is nonagouti. Finally, the color of the pigment may be black (B-) or brown (bb). Five different coat colors may be produced by the action of...
In the same mouse species, a fourth unlinked gene (gene P/p) also affects fur color. For mice...
In the same mouse species, a fourth unlinked gene (gene P/p) also affects fur color.For mice that are either homozygous dominant (PP) or heterozygous (Pp), the organism’s fur color is dictated by the other three genes (A/a, B/b, and C/c).For mice that are homozygous recessive (pp), large patches of the organism’s fur are white. This condition is called piebaldism.In a cross between two mice that are heterozygous for agouti, black, color, and piebaldism, what is the probability that offspring will...
7. In mice the coat color called agouti results from a dominant allele A. Mice that...
7. In mice the coat color called agouti results from a dominant allele A. Mice that are AA or Aa have agouti fur. Mice that are aa have black fur. However to get any coat color at all, at least one copy of a second dominant allele C of a different locus must be present. If a mouse has genotype cc, the mouse is albino regardless of what is happening at the other gene pair. Suppose two mice with genotypes...
In rats, several independently assorting autosomal genes affect coat color. Gene A controls the distribution of...
In rats, several independently assorting autosomal genes affect coat color. Gene A controls the distribution of yellow pigment in hair, and gene B causes black pigmentation. The two genes interact as follows: A–B– (gray), A–bb (yellow), aaB– (black), and aabb (cream). These genotypes are only expressed in the presence of the dominant allele of a third gene, C; rats with genotype cc are albino. a. Deduce the genotype of each albino mice, to the extent that is possible, in the...
/ fn Labrador retrie brown coat color however, the E gene controls expression of the B...
/ fn Labrador retrie brown coat color however, the E gene controls expression of the B gene. The B and E genes interact to yield 3 phenotypes: black (B_E), chocolate (bbE) and yellow ee). What is the phenotypic ratio of the pups that might result vers, the B allele confers black coat color and the b allele from a cross between a yellow female (Bbeo and a chocolate male (hb Be) Coat color in Labrador retrievers is an example of...
- Vi tal:ros. b The agouti gene determines coat colour in mice. Heterozygous mice have yellow...
- Vi tal:ros. b The agouti gene determines coat colour in mice. Heterozygous mice have yellow coats, while homozygous dominant mice have black coats. However, having two copies of the recessive alleles is lethal. In a population of 2000 mice, 1082 mice have black coats. Calculate the frequency of each altele. Show all your work and express your answer as a value between 0 and 1 rounded to two decimal places. (3 marks) B 15 E U ch X2 x...
QUESTION 15 In Labrador retrievers, there are 3 gene products involved in determining coat color: gene...
QUESTION 15 In Labrador retrievers, there are 3 gene products involved in determining coat color: gene product B, gene product E, and gene product C. B produces a melanin pigment such that B/B and B/b will produce a black lab while b/b (with less melanin produced) will result in a chocolate lab. However, for the B gene to be expressed, a signaling hormone (gene E product) must be produced to activate transcription of the B gene. E is fully dominant...
19. Two different gene loci are responsible for determining mouse coat color. A recessive lethal allele contributing to yellow coat color also exists for one of these two gene loci. The following genotypic and phenotypic information about the mouse coat color alleles is known: (6) Agouti = A-B- • Yellow = AA'B-or A'aB-or A'ab- Lethal (inviable zygote) = A'A- Black = aaB- Albino = -bb a. A cross is made that produces 2 yellow, 1 black, and 3 albino mice....
1. At least 3 independently assorting loci are known to govern coat color in mice. The genotype C- will allow pigment to be produced by 2 other genes. The cc genotype does not allow pigment production resulting in albino mice. The striped “agouti” hair pattern depends on the genotype A- and the aa genotype is nonagouti. Finally, the color of the pigment may be black (B-) or brown (bb). Five different coat colors may be produced by the action of...
7. In mice the coat color called agouti results from a dominant allele A. Mice that are AA or Aa have agouti fur. Mice that are aa have black fur. However to get any coat color at all, at least one copy of a second dominant allele C of a different locus must be present. If a mouse has genotype cc, the mouse is albino regardless of what is happening at the other gene pair. Suppose two mice with genotypes...
/ fn Labrador retrie brown coat color however, the E gene controls expression of the B gene. The B and E genes interact to yield 3 phenotypes: black (B_E), chocolate (bbE) and yellow ee). What is the phenotypic ratio of the pups that might result vers, the B allele confers black coat color and the b allele from a cross between a yellow female (Bbeo and a chocolate male (hb Be) Coat color in Labrador retrievers is an example of...
- Vi tal:ros. b The agouti gene determines coat colour in mice. Heterozygous mice have yellow coats, while homozygous dominant mice have black coats. However, having two copies of the recessive alleles is lethal. In a population of 2000 mice, 1082 mice have black coats. Calculate the frequency of each altele. Show all your work and express your answer as a value between 0 and 1 rounded to two decimal places. (3 marks) B 15 E U ch X2 x...
QUESTION 15 In Labrador retrievers, there are 3 gene products involved in determining coat color: gene product B, gene product E, and gene product C. B produces a melanin pigment such that B/B and B/b will produce a black lab while b/b (with less melanin produced) will result in a chocolate lab. However, for the B gene to be expressed, a signaling hormone (gene E product) must be produced to activate transcription of the B gene. E is fully dominant...
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