Consider a magnetic disk that has 1,764 cylinders, 500 sectors per track (on average), 0.07 milliseconds minimum seek time, and 5,376 rpm rotational speed. Assume that the disk heads have a constant speed. Each sector is 512 bytes, and each block is four sectors.
What is the average rotational delay in milliseconds (rounded to no decimal places)?
Average rotational delay is nothing but half the time taken by a disk to complete one revolution.
As per the details given in the
question, the disk is rotating at 5376 RPM.
Using the unitary method to find the rotational delay:
Therefore avg. rotational delay =
half the time taken by a disk to complete one revolution
= 1/2 x 11.16 milliseconds = 5.58 = 6 milliseconds
(rounded figure)
Consider a magnetic disk that has 1,764 cylinders, 500 sectors per track (on average), 0.07 milliseconds...
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