Question

Consider a magnetic disk that has 1,764 cylinders, 500 sectors per track (on average), 0.07 milliseconds...

Consider a magnetic disk that has 1,764 cylinders, 500 sectors per track (on average), 0.07 milliseconds minimum seek time, and 5,376 rpm rotational speed. Assume that the disk heads have a constant speed. Each sector is 512 bytes, and each block is four sectors.

What is the average rotational delay in milliseconds (rounded to no decimal places)?

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Answer #1

Average rotational delay is nothing but half the time taken by a disk to complete one revolution.

As per the details given in the question, the disk is rotating at 5376 RPM.
Using the unitary method to find the rotational delay:

  • 5376 rotations in 1 minute.
  • 5376 rotations \rightarrow 1 minute  
  • 5376 rotations \rightarrow 60 seconds
  • 1 rotation \rightarrow (60 seconds) / 5376
  • 1 rotation \rightarrow (60 x 1000 milliseconds) / 5376
  • 1 rotation \rightarrow 11.16 milliseconds

Therefore avg. rotational delay = half the time taken by a disk to complete one revolution
= 1/2 x 11.16 milliseconds = 5.58 = 6 milliseconds (rounded figure)

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