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Suppose we have a magnetic disk with the following parameters : • Average seek time =...

Suppose we have a magnetic disk with the following parameters : • Average seek time = 6 ms • Rotation rate = 5400 RPM • Transfer rate = 100 MB/second • Sector size = 512 bytes What is the average time to read a single sector?

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Answer #1

Disk Access Time = seek time + rotational delay + transfer time + controller overhead = 6+(0.5*60*10^3 /5400) + (512/(100*2^20))*1000 = 11.556 ms

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