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Given the following data: 3 s(s) + 2O2(9) S03(9) AH = -395.2 kJ 2802(g) + O2(g)...
Given the following data: S(s) + 02(8) -> SO3(g) AH = -395.2 kJ 2SO2(g) + O2(g) + 2503(g) AH = - 198.2 kJ Calculate AH for the reaction: S(s) + O2(g) SO2(g) +296.1 kJ -494.3 kJ -296.1 kJ 0 -197.0 kJ -593.4 kJ
IS LOCAS Question 16 5 pts Given the following data: S(s) + O2(g) → SO3(8) AH=-395.2 kJ 2502(g) + O2(g) - 2503(g) AH = - 198.2 kJ Calculate AH for the reaction: S(s) + O2(g) +SO2(g) -197.0 kJ 0 -593.4 kJ -296.1 kJ -494.3 kJ +296.1 kJ 5 pts Question 17
1). From the following enthalpy changes, S (s) + 3/2 O2 (g) → SO3 (9) 2 SO2 (g) + O2(g) → 2 SO3 (9) AH° = -395.2 kJ AH° = -198.2 kJ Calculate the value of AH° for the reaction by using Hess's law of Heat Summation S (s) + O2 (g) → SO2 (g).
For the reaction 2802(g) + O2(g)—>2503(g) AH° = -197.8 kJ and AS° = -187.9 J/K The equilibrium constant for this reaction at 298.0 K is Assume that AHⓇ and AS™ are independent of temperature.
QUESTION 7 Calculate the enthalpy (AH) for the following equation: 2S(s) + 302(g) +2503(g) from the data shown below. S(s) + O2(g) → SO2(8) AH = -297 kJ 2503(8) ► 2802(g) + O2(8) [see module 9] AH = 198 kJ 0-99 kJ O-693 kJ O-396 kW O -792 KW -17
For the reaction 2802(g) + O2(g) -2503(g) AH° = -197.8 kJ and AS° = -187.9 J/K The equilibrium constant for this reaction at 277.0 K is Assume that AH° and ASº are independent of temperature.
s(s) + 3/2 O2 (g) = SO3 15. (6 pts) Given the data below, calculate the ΔΗ,xn for the reaction: AH -296.1 kJ S (s) + O2 (g) → SO2 (g) 2SOs (g)
1).From the following enthalpy changes, S (s) +3/2 O2 (g) 2 SO2 (g) SO3 (g) O2 (g)2 SO3 (g) AH =-395.2 kJ AHo 198.2 kJ Calculate the value of AHo for the reaction by using Hess's law of Heat Summation S(s) O2 (g) SO2 (g) 2) Oxyacetylene torches are fueled by the combustion of acetylene, C2H2. 4 CO2 (g) +2 H20 (g) 2 C2H2 + 5 O2 (g) If the enthalpy change for the reaction is -2511.14 kJ/mol, a) How...
AG° = -300.1 kJ AG° =-742.1 kJ 4. Given that S(g) + O2(g) → SO2(g) 2S(g) + 302(g) → 2503(g) calculate AG of the following reaction: SO2(g) + 1/2O2(g) → SO3(g) a. –1042.2 kJ b. -71.0 kJ c. +2.47 kJ d. +71.0 kJ e. +1042.2 kJ
You are given the following data. AH = = -286.0 kJ H2(g) + 1/2O2(g) → H20(1) N2O5(9) + H20(1) → 2 HNO3(aq) 1/2 N2(9) + 3/2 02(9) + 1/2 H2(9) AH = -77.0 kJ HNO3(1) AH = -174.0 kJ Calculate the AH for the reaction given below. 2 N2(g) + 5 O2(g) → 2 N205(9) k] Need Help? Read It Supporting Materials Periodic Table E Constants & Factors Supplemental Data