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D. Here are several pairs of charged particles. For each pair, draw two arrows, one for the force felt by the right-hand part
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+29 +29 I ** Fron L FOOR (b +4q ܠܐܐܐ 79 1 1 1 1 Force on +49 due to tq EonR kq F Force on a due to tuq = 4K9 22 4F, x2 +29 +92 E = KX2X10 (0.22 qx16x2xion 0.04 - 9X 10PXIX10-9 = 450 N/c. Ez = KX ix 10 (0.1)? - 900 NLC 0.01 : net Electric field = 900-

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