Question

Exercise 2: Generating Electricity with a moving Bar Two going through them in resistance is R. A sliding metalic bar with no electrical resistance is made to move to the right ntol parallel conducting rails are placed a distance I apart with a magnetic field B to the paper. The rails are connected with a fixed wire whose electrical with a constant speed v (left side of diagram above) a. In order to be consistent with electrical circuit theory, we will assume that a conductor has freely moving positively charged particles in it (with charge e), whose net motion creates an electrical current. Using the Lorentz force equation [F qlv x B)] write an expression for the magnitude of the force on each charged particle inside the metallic bar Mark the direction of the Lorentz force with an arrow drawn inside the bar in the left diagram. (Use the right hand rule to figure out the direction). b. The Lorentz force will move the positive charges through the bar into one rail and through the wire into the other rail, creating an electrical current through this closed circuit. As the current moves through the resistance it will create a potential difference (voltage) between the two ends of the wire On the left diagram mark the direction of the current with an arrow. One end of the wire has a higher potential. Mark the ends of the wire with a+ for high and -for low potential. c. Since the rails have no resistance, the same potential difference must exist between the two ends of the bar. Mark the ends of the bar with + and- to indicate the voltage direction. d.

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Answer 1