Question

8. In a sample of 150 Americans, 30 said that they do not watch local TV channels, Use 95% confidence level to estimate the proportion of Americans who do not watch Local TV channels. Express your answer in Pain <p 2 Pmax. the form

please show work(z critical value, error of margin calculation,p max and p min).

Answer 1

(i)

n = 150

$\hat{p}$ =30/150 = 0.2

$\alpha$ = 0.05'

From Table,

critical values of Z = $\pm$ 1.96

(ii)

Margin of Error (E) is given by:

E = 2 x V x (1 - p/n = 1.96 0.2 x (1 – 0.2) 150 = 0.0640

(iii)

pmax = 0.2 + 0.0640 = 0.2640

(iv)

pmin = 0.2 - 0.0640 = 0.1360

So,

Confidence Interval:

0.1360 < p < 0.2640