Question

Find the mean, median, and mode for the given distribution. 6,4,3, 9, 11, 6, 6, 4, 9, 11, 6, 3, 13, 9, 6, 6, 3, 4, 9, 6 O A. Mean = 6.70, median = 6, mode = 6 OB. Mean=6.70, median = 9, mode = 6 O C. Mean = 6.70, median = 6, mode = 13 O D. Mean = 7.20, median=6, mode = 13

Answer 1

Correct option

A   Mean = 6.70,   median = 6, mode = 6

Explanation:

Mean () is given by:

T

$\bar{x}=\frac{\sum_{i=1}^{20}x_{i}}{20}=\frac{134}{20}=6.70$

Arranging numbers in ascending oder:

3,3,3,4,4,4,6,6,6,6,6,6,6,9,9,9,9,11,11,13

Median is (20+1)/2th item = Average of 1oth & 11th item = (6 + 6)/2 = 6

So,

Median= 6

mode = 6

because 6 occurs maximum number oftimes in the dataset.