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The strong acid H2SeO4 will completely ionize in water, however the conjugate base can then act...

The strong acid H2SeO4 will completely ionize in water, however the conjugate base can then act as a acid an ionize further.

The second Ka, Ka2 for HSeO4 is 1.2 x 10-2.    This second Ka is not insignificant, being stronger than many other weak acids.

A. Calculate the [H3O+] for a solution of 0.150 M H2SeO4.

B. Using the value calculated above, calculate the value of [H3O+] for both ionizations of the acid. Grading will be based on the follow:

Write the chemical equation for the second ionization of the acid, include phase symbols and any charges.

Determine if the S.A. is valid, show your work.

Construct the ICE table.

Solve for [H3O+]

NOTE: Calculation A should be easy as it's a strong acid. For B, write the chemical equation for the second ionization, construct the ICE table, check the S.A., if valid....good, if not, well, you know what to do. Solve for the [H3O+]. Show every step, if using a program indicate your values for a, b, & c. Express answer to the correct SF's.

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