Question

Constants Pe A 975-kg two-stage rocket is traveling at a speed of 6.30x10 m/s away from Earth when a predesigned explosion separates the rocket into two sections of equal mass that then move with a speed of 3.00x109 m/s relative to each other along the original line of motion Part A What is the speed of each section (relative to Earth) after the explosion? Enter your answers numerically separated by a comma. να ΑΣΦ 2 x xVx x x x x x.109 U Your submission doesn't have the correct number of answers. Answers should be separated with a No credit lost. Try again Submit Previous Answers Request Answer

Answer 1

= m = 975 kg V = 6.3 x 103 ری given data mis va velocity of faster half after separation Vo = velocity of slower half after separation giren. » Va-vo 3 x 103 mis Initial momentum, Py = m v -> final 9 momentun mvá mvh + 2 Pf 10 쁠 2 8 Pf m (vá + vó

By using conservation of Momentum Pi 90 2 o. 2V + VÝ { from Ean m. Vs m (vá + vos vat vó 2.2V = (vý + 3x103) + Vý C. V VE V + 1.5x163 = V - (1.5 x103) = (6.3 x 103)-11-5x103) 4.8 X10 vo vo mis from Ean

vá Vot (3x103) 103) + (3 x 103) = (4.8 x 10 3 val 7.8 x 10 Skee B) Energy Supplied by Explosion - KE = 1 me? KEf KE; = (( )wa+ ( 9 ) (103) -(1mv²) [cvas 2 ..AK = m (vo)] - m +

+ Дk = 925 (1.8x1032 प (4.8 x 103) 4s (6.3 x 1 - 2. ?. ДК - (204us .+5 x 10° ) -(19348.82 x 106 ) 2. ДК - To46.8 x 166 о. ДК 2 9 1.690 x 10"