Question

Please show all work if needed.

14. (III) A 725-kg two-stage rocket is traveling at a speed of 6.60 x 103 m/s away from Earth when a predesigned explosion separates the rocket into two sections of ed mass that then move with a speed of 2.80 x 103 m/s relati to each other along the original line of motion. (a) What is the speed and direction of each section (relative to Earth after the explosion? (b) How much energy was supplied by the explosion? (Hint: What is the change in kinetic energy as a result of the explosion?]

Answer 1

my a p nim, = "72 lange 1 = m.olx initially before the after the explosion. explosion teelu. 1 Total man of the combined body, (m, &m2) = m. (d) o prerang (%o1x ə-) xatm = 275 kg., . initial velocity of the body (combined), v=6*6*103 eltooix e 8 e.al After explosion, the mass of each part, mi= mam 275 kglo berth m/s Blerin Lorettive = 137.5 kg..

say, After explosion, the velocity of mass m, is vir and the velocity of mass me is Vr. So, uning conservation of momentum principle before and after the explosion me get mxv=more + m2 V or wiem xv=mY & m va iste on, tv = 2 Juta And another data is given that relative speed between of the parts, ine) - (Vi-v2 = 28 x 10 m/ sname so by adding equation and equation , we get 2V, = (2x V) 1 (2.8x103) m/s enize que mawb = (2x 696x103)+(268x103) que chega Denne ugerens tervis et = 16 x 10 m/ s or v = 16x16? - 8x10 3 m/s. & V2 = (2V - V.) = (2x 66x 103 – 8x103) = 5.2X103 m/s,

speed of one section, V. = 8x10 m/s and speed of another section, V2 = 15 • 2x10 m/s.) nozolguns enthal t enofed allurbus 6 Now before the explosion we see, the kinetic e energy of the total body maso orxad = V (K. E.). - m - 1 x 275 x (6.6x103) Jule = 5.989 x 10 Jule. olsu sitinis

explosion hiru collision the total kinetic energy of both And, after parts N (K.Ev) = 1 m rin + 1 mq var Liim), + m V2 i = (6.366 x 10] Jule per change in kinetic energy in eo explosion O o k E. = (K.E) f -(.e.) i 192 ustalare – 16:366-50989]xio? Jule = =(0:37 7 x109) Jules i. This amount of extera kinetic energy is. supplied by the explosion and there fore. the kinetic energy is gained by an amount of OKE (0x88) 1 (V x S) = ,Vs splied to the rockets, during explosion, E = AK.E. = 0.377 x 10 Jule or, E = 3.77 x 108 Jule) n. *** )= GV-V) = 1