Answer:
Given,
sample n = 10
Ho : u2-u1 = 0
Ha : u2-u2 !=0
test statistic t = (x - u)/(s/sqrt(n))
substitute values
= 2.75
degree of freedom = n - 1 = 10 - 1 = 9
alpha = 0.01
Critical value = t(alpha/2 , df) = t(0.01/2 , 9) = 2.8214
P value = 0.022477
= 0.0225
p value > alpha
Here we observe that, test statistic < critical value, so we fail to reject Ho.
So there is no sufficient evidence to support the claim.
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