At a certain university, the average attendance at basketball
games in the previous year was
3000 spectators per game. For the first 12 games of the current
year, there has been an average
of 2400 spectators per game with a standard deviation of 450.
The athletic director claims that the attendance is the same as
last year.
At the α = .05 significance level, is there evidence to support his
claim?
Group of answer choices
1*Because t = -4.16 is not in the rejection region, there is not significant evidence to refute the athletic director's claim.
2*Since p = .0007, there is significant evidence that the
attendance this year is different
from the previous year.
3*Since the p-value is less than the critical value, there is
not enough evidence to reject
the athletic director's claim.
Solution:
Null and alternative hypotheses:
Excel output:
Hypothesis Test: Mean vs. Hypothesized Value | ||||
3,000.00 | hypothesized value | |||
2,400.00 | mean attendance | |||
450.00 | std. dev. | |||
129.90 | std. error | |||
12 | n | |||
11 | df | |||
-4.62 | t | |||
.0007 | p-value (two-tailed) |
Here, t-statistic is, t = -4.62
P-value = 0.0007
Decision: P-value = 0.0007< 0.05, reject H0.
Conclusion: Since p = .0007, there is significant evidence that
the attendance this year is different
from the previous year. (Option 2 is correct)
Done
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