Question

Question 2 ases 5 pts Je Use the confidence level and sample data to find a confidence interval for estimating the population u. Find the margin of error E and round your answer to the nearest tenth. n 49, = 87,5 - 12: 90% confidence Question 4 5 pts Use the confidence level and sample data to find a confidence interval for estimating the population p. Round your answer to the nearest tenth, if necessary. Test scores: n - 100 E = 92,0 - 20; 90% confidence 83.8 << 86.8 88.7 <u< 95.3 94.1 << 96.5 942 << 96.4 Identify the null hypothesis, alternative hypothesis, test statistic, P-value, conclusion about the null hypothesis, and final conclusion that addresses the original claim. The health of employees is monitored by periodically weighing them in. A sample of n = 54 employees has a mean weight of 8 = 190 lb. Assuming that o - 25 lb, use a 0.01 significance level to test the claim that the population mean of all such employees weights is less than 200 lb. Hofu - 200 Hz:H< 200; Test statistic: 2--2.94. P-value: 0.0016. Since the P.Value is smaller than the significance level of 0.05, we reject Ho. There is sufficient evidence to support the claim that the mean is less than 200 pounds. Ho: H - 190; H2 H > 190; Test statistic: 2 - 2.94. P-value: 0.9984. Since the P.Value is larger than the significance level of 0.05, we fail to reject Ho. There is not sufficient evidence to support the claim that the mean is greater than 190.

Answer 1

Solution Question 2 : given : n=49 p=87 SE 12 a=0.10 The eodo margin of E = t 12 الي 1,677 * Jug E =12.874857 A gol. Ce for C'I for population medini 시 7 I E F:0.87 I 2.874857 Ans: The margin of enor € = 2.9 A got C.I [184.1 for population 89.9]

Question 41- given in m = 100 20 X = 92 = 0.10 А go CiI. for Population mean l- X I z un - 1.645 X 20 vioo = ☆ + 3.29 92 £ 3.29 u Ans : ₃ A gopa mean C'I for population I 88.71 95.2g Round your answer to the nearest fenth 95.3 M= 88. 7 Question: given :- n=54 ă = 190 lb Q=0.01 O: 2516 Ans: و Hoi l = 200 is Hiiu<200 Test statistic: Z = -2.94 = -2.94 P-voolue = 0.0016, since the p-value is smaller than the Tois. 0.05 we reject to there is sufficient evidence to support the claim that the mean is less than 200 pounbs.