Question

Question 18 (1 point) The health of employees is monitored by periodically weighing them in. A sample of 54 employees has a mean weight of 183.9 lb. Assuming that is known to be 121.2 Ib, use a 0.10 significance level to test the claim that the population mean of all such employees weights is less than 200 lb. List values for blanks only. Round calculated values to 3 decimal places. HO: На: Test statistic P-value = We There the null hypothesis. sufficient evidence to support the claim.

Answer 1

Solution:

1)

H0 : $\mu$ = 200

2)

Ha : $\mu$ <  200

3)

Test statistic z = $[\bar x-\mu]/[\sigma/\sqrt{n}]$ = [183.9 - 200]/[121.2/$\sqrt{}$54] = -0.976

Test statistic = -0.976

3)

Left tailed test

p value = P(Z < -0.976) = 0.1645

p value = 0.1645

4)

We fail to reject the null hypothesis

(Because p value is greater than the level of significance)

5)

There is not sufficient evidence to support the claim